xsl-list
[Top] [All Lists]

Re: Grouping problem?

2003-04-23 02:37:35
Damn it again!!

Here is the tail recursion version!!

<xsl:template match="ele">
  <xsl:choose>
    <xsl:when test="position() = 1">
      <xsl:variable name="count" select="sum(./@sum)" />
    </xsl:when>
    <xsl:when test="$count < 10">
      <xsl:choose>
        <xsl:when test="($count + sum(./@sum)) >= 10">
          <br/>
          <xsl:variable name="count" select="sum(./@sum)" />
        </xsl:when>
        <xsl:otherwise>
          <xsl:variable name="count" select="$count + sum(./@sum)" />
        </xsl:otherwise>
      </xsl:choose>
    <xsl:otherwise>
      <br />
      <xsl:variable name="count" select="sum(./@sum)" />
    </xsl:otherwise>
  </xsl:choose>
  <xsl:copy>
    <xsl:apply-templates select="node()|@*" />
  </xsl:copy>
</xsl:template>

Cheers

Simon


----- Original Message -----
From: "Simon Kelly" <kelly(_at_)ipe(_dot_)fzk(_dot_)de>
To: <xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com>
Sent: Wednesday, April 23, 2003 11:25 AM
Subject: Re: [xsl] Grouping problem?


Damn.

I think I got something wrong with the <xsl:apply-templates
select="node()|@*" /> line.  I just wanted to pass in the next sibling not
the entire node set.  And I'm not 100% sure this isn't going to overflow
on
very large node sets either.

Cheers

Simon


----- Original Message -----
From: "Simon Kelly" <kelly(_at_)ipe(_dot_)fzk(_dot_)de>
To: <xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com>
Sent: Wednesday, April 23, 2003 11:13 AM
Subject: Re: [xsl] Grouping problem?


Hi Benjamin,

I can't actually test this solution as I don't use saxon, but if you can
then this may work out ok.


Up the top somewhere define an assignable variable

<xsl:variable name="count" select="0" saxon:assignable="yes" />

then

<xsl:template match="/root">
  <xsl:apply-templates />
</xsl:template>

<xsl:template match="ele">
  <xsl:choose>
    <xsl:when test="position() = 1">
      <xsl:variable name="count" select="sum(./@sum)" />
      <xsl:copy>
        <xsl:apply-templates select="node()|@*" />
      </xsl:copy>
    </xsl:when>
    <xsl:when test="$count < 10">
      <xsl:choose>
        <xsl:when test="($count + sum(./@sum)) >= 10">
          <br/>
          <xsl:variable name="count" select="sum(./@sum)" />
          <xsl:copy>
            <xsl:apply-templates select="node()|@*" />
          </xsl:copy>
        </xsl:when>
        <xsl:otherwise>
          <xsl:variable name="count" select="$count + sum(./@sum)" />
          <xsl:copy>
            <xsl:apply-templates select="node()|@*" />
          </xsl:copy>
        </xsl:otherwise>
      </xsl:choose>
    <xsl:otherwise>
      <br />
      <xsl:variable name="count" select="sum(./@sum)" />
      <xsl:copy>
        <xsl:apply-templates select="node()|@*" />
      </xsl:copy>
    </xsl:otherwise>
  </xsl:choose>
</xsl:template>


It's a bit long winded but it should work.  The last <xsl:otherwise />
in
the main <xsl:choose /> takes care of any first nodes that are greater
than
10.  This should also work for any ele grouping like

<root>
  <set val="1">
    <ele sum="1" />
    ...
    <ele sum="n" />
  </set>
  <set val="N">
    <ele sum="2" />
    ...
    <ele sum="N" />
  </set>
</root>

with a minor mod to the calling template.

Cheers

Simon


----- Original Message -----
From: "Benjamin Farrow" <lovinjess(_at_)hotmail(_dot_)com>
To: <xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com>
Sent: Tuesday, April 22, 2003 9:06 PM
Subject: [xsl] Grouping problem?


All,
  I don't know how to explain my problem in words very concisely, so
I'll
try with a simplified example.

SourceXML:
<root>
  <ele sum="3"/>
  <ele sum="4"/>
  <ele sum="2"/>
  <ele sum="10"/>
  <ele sum="7"/>
  <ele sum="5"/>
  <ele sum="1"/>
  <ele sum="2"/>
</root>

Desired Output:
<root>
  <ele sum="3"/>
  <ele sum="4"/>
  <ele sum="2"/>
  <br/>          <!-- next element makes total greater than 10 -->
  <ele sum="10"/>
  <br/>          <!-- next element makes total greater than 20 -->
  <ele sum="7"/>
  <br/>          <!-- next element makes total greater than 30 -->
  <ele sum="5"/>
  <ele sum="1"/>
  <ele sum="2"/>
</root>

I'm trying to break apart the ele element when the sum total of
preceding
siblings and self is greater than the increment of 10 by putting an
element
to denote the break.

I've tried some crazy tests with mod and div and I've looked over the
Muenchian grouping, but I still can't come up with a way to
arbitrarily
set
the break points.  I know there is a solution and I get close, but I
just
can't get around it.

Here is my template (also have the standard identity template) with
which
I'm trying to get this working.  I just can't figure out the if test
for
this though.

XSL:
  <xsl:template match="ele">
    <xsl:variable name="sum"
select="sum(preceding-sibling::ele/@sum|@sum)"/>
    <xsl:if test="$sum &gt; (floor($sum div 10) * 10)">
      <br/>
    </xsl:if>
    <xsl:copy>
      <xsl:apply-templates select="node()|@*"/>
    </xsl:copy>
  </xsl:template>

Thanks in advance,
  Benjamin


_________________________________________________________________
MSN 8 with e-mail virus protection service: 2 months FREE*
http://join.msn.com/?page=features/virus


 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list




 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list




 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list




 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list



<Prev in Thread] Current Thread [Next in Thread>