<xsl:when test="position()%2=0">

first of all i wish to thank all of you guys (and gals) for providing me
with great help. now i have another query

i would like to find the position of a node whether it is odd or even, and
tried to use position() mod 2, but i don't know how to do it

can anyone tell me how to find the remainder of a division or else any ideas
on how to find whether a node is odd or even

10x, regards 
luke