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RE: Counting uniquely selected values of elements

2003-04-14 22:55:12
Hi,

The a and b elements are always there but there might be some 
(d) elements 
before the c element: a/b/d/c, perhaps a/b/d/e/f/c.

Kan I in the solution below, just substitute a/b/c with a/b//c?

In the key match you can use

  <xsl:key name="uniq" match="c" use="." />

if c is not used as a non-countable item. If a/b//c selects all the c elements 
you want, then it'll work.

Cheers,

Jarno - Clan of Xymox: I Want You Now

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