Is there any concept like passing command line arguments in XSLT
-----Original Message-----
From: Sundar Shanmugasundaram
[mailto:SSHANMUGASUNDARAM(_at_)selectica(_dot_)com]
Sent: Wednesday, May 14, 2003 11:07 AM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: [xsl] Passing inputs to an XSLT
Karthick,
You can give <xsl:param> inside <xsl:template>. Include your xsl file in
the
file which has to call this xsl file. And use the call-template with
with-param.
sundar
-----Original Message-----
From: Karthickraj N - CTD, Chennai.
[mailto:karthickrajn(_at_)ctd(_dot_)hcltech(_dot_)com]
Sent: Wednesday, May 14, 2003 11:08 AM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Passing inputs to an XSLT
Hello friends,
I wanted to pass a string as input to an XSLT file, which will then be used
as a variable in the XSLT file.
If anyone could find a solution please help me out.
Thanx in advance,
Regards,
Karthickraj
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list