Hi,
Erm... why not just use xsl:param as a top-level instruction
<http://www.w3.org/TR/xslt#top-level-variables> and pass the string using the
processor's API?
Cheers,
Jarno
You can give <xsl:param> inside <xsl:template>. Include your
xsl file in
the
file which has to call this xsl file. And use the call-template with
with-param.
sundar
-----Original Message-----
From: Karthickraj N - CTD, Chennai.
[mailto:karthickrajn(_at_)ctd(_dot_)hcltech(_dot_)com]
Sent: Wednesday, May 14, 2003 11:08 AM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Passing inputs to an XSLT
Hello friends,
I wanted to pass a string as input to an XSLT file, which
will then be used
as a variable in the XSLT file.
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list