Are you looping through each "title" and "episode" element?, or is their
only one "title" and one "episode" element ?
If their will only be one element of each, why not reference the element
using the full path to it.
<xsl:if test="starts-with(encyclopedia/entry/title, 'Q') or
starts-with(encyclopedia/entry/episode, 'Q')">
<xsl:call-template name="inserted.text"/>
</xsl:if>
I know of another way if you have to loop through eacg title and episode,
but I'll wait to see your reply
-----Original Message-----
From: owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
[mailto:owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com]On Behalf Of Ben
Trafford
Sent: Wednesday, 7 May 2003 10:30 a.m.
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] XPath question.
I have a problem, and no doubt the answer is simple...
I have the following XSLT snippet:
<xsl:if test="starts-with(//title, 'Q') or starts-with(//episode, 'Q')">
<xsl:call-template name="inserted.text"/>
</xsl:if>
The document structure it applies to is like so:
<encyclopedia>
<entry>
<title>A Title</title> -or- <episode>An episode
name.</episode>
</entry>
</encyclopedia>
The <xsl:if/> referenced above happens at the <encyclopedia/> level.
I just want to call the template "inserted.text" if the title or episode
do not start with the letter 'Q'.
As it is, I can't get the inserted.text to appear...no matter what I do.
Am I walking down the node tree incorrectly?
--->Ben
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
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