Google "Muenchian method".
--
Charles Knell
cknell(_at_)onebox(_dot_)com - email
-----Original Message-----
From: Jeroen Janssen <jeroen(_at_)laika(_dot_)nl>
Sent: Thu, 26 Jun 2003 15:41:04 +0200
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] 2 level grouping
I have a problem that I have been trying to find the solution for for
quite a while, but frankly it's a bit too complicated for my limited
xsl skills, maybe someone on this list can point me in the right
direction.
I have something like this:
<items>
<item month="5" year="2003"/>
<item month="5" year="2003"/>
<item month="4" year="2003"/>
<item month="3" year="2003"/>
<item month="2" year="2003"/>
<item month="1" year="2003"/>
<item month="12" year="2002"/>
<item month="11" year="2002"/>
<item month="10" year="2002"/>
<item month="9" year="2002"/>
</items>
And as a result I would like a list of all the months and all the
years, with no duplicates. Something like this:
5/2003
4/2003
3/2003
2/2003
1/2003
5/2002
ect. you get the idea...
Now if it was just the months I could (with a little help from google)
write an xsl that would work. But the years make it much more
complicated.
Hopefully I'm making myself clear here...
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