Hi Américo,
Thanks alot. Its working.
Ashis, My XML will have the data in consecutive order. So no problem.
Thanks,
Jay
From: "Tengshe, Ashish" <Tengshe(_dot_)Ashish(_at_)principal(_dot_)com>
Reply-To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
To: <xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com>
Subject: RE: [xsl] No to display the values which are already existing
Date: Wed, 25 Jun 2003 13:13:31 -0500
This is not really accurate. This works only for th given sequence, try
placing "Dan" and "Steve" Authors in different sequence and this breaks.
Basically this works only if the Element on which the key is generated are
in consecutive order.
I would like the answer too!
Thanks,
Ashish
-----Original Message-----
From: Américo Albuquerque [mailto:melinor(_at_)sapo(_dot_)pt]
Sent: Wednesday, June 25, 2003 12:48 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: [xsl] No to display the values which are already existing
Hi
> -----Original Message-----
> From: owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
> [mailto:owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com] On Behalf Of
> Dhananjay Pitani
> Sent: Wednesday, June 25, 2003 6:23 PM
> To: XSL-List(_at_)lists(_dot_)mulberrytech(_dot_)com
> Subject: [xsl] No to display the values which are already existing
>
>
> This is my xml
>
> <Store>
> <Title>
> <Author>Steve</Author>
> <Name>XSL</Name>
> </Title>
> <Title>
> <Author>Steve</Author>
> <Name>XML</Name>
> </Title>
> <Title>
> <Author>Dan</Author>
> <Name>HTML</Name>
> </Title>
> <Title>
> <Author>Dan</Author>
> <Name>XSL</Name>
> </Title>
> </Book>
>
> I want to display the above xml as a html table with two
> columns Author and
> Titlle. My task is to display the Author's name only once.
> The output should
> be like this
>
> Author Title
>
> Steve XSL
> XML
> Dan HTML
> XSL
>
You could use a variation of the muenchian method
<xsl:key match="Title" name="list" use="Author"/>
<xsl:template match="Store">
<table>
<tr>
<td>Author</td>
<td>Title</td>
</tr>
<!-- instead of applying just to the first element of each group apply
to
all -->
<xsl:apply-templates/>
</table>
</xsl:template>
<xsl:template match="Title">
<tr>
<td>
<!-- display the Author if this is the first element of the group -->
<xsl:if test="generate-id()=generate-id(key('list',Author))">
<xsl:apply-templates select="Author"/>
</xsl:if>
</td>
<td>
<xsl:apply-templates select="Name"/>
</td>
</tr>
</xsl:template>
Hope this helps you.
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