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RE: No to display the values which are already existing

2003-06-25 11:13:31
This is not really accurate. This works only for th given sequence, try placing 
"Dan" and "Steve" Authors in different sequence and this breaks. Basically this 
works only if the Element on which the key is generated are in consecutive 
order.
I would like the answer too!
Thanks,
Ashish

-----Original Message-----
From: Américo Albuquerque [mailto:melinor(_at_)sapo(_dot_)pt]
Sent: Wednesday, June 25, 2003 12:48 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: [xsl] No to display the values which are already existing


Hi

-----Original Message-----
From: owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com 
[mailto:owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com] On Behalf Of 
Dhananjay Pitani
Sent: Wednesday, June 25, 2003 6:23 PM
To: XSL-List(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] No to display the values which are already existing


This is my xml

<Store>
  <Title>
        <Author>Steve</Author>
        <Name>XSL</Name>
  </Title>
  <Title>
        <Author>Steve</Author>
        <Name>XML</Name>
  </Title>
  <Title>
        <Author>Dan</Author>
        <Name>HTML</Name>
  </Title>
  <Title>
        <Author>Dan</Author>
        <Name>XSL</Name>
  </Title>
</Book>

I want to display the above xml as a html table with two 
columns Author and 
Titlle. My task is to display the Author's name only once. 
The output should 
be like this

Author      Title

Steve        XSL
                XML
Dan           HTML
                XSL


You could use a variation of the muenchian method

 <xsl:key match="Title" name="list" use="Author"/>
 <xsl:template match="Store">
  <table>
   <tr>
    <td>Author</td>
    <td>Title</td>
   </tr>
   <!-- instead of applying just to the first element of each group apply to
all -->
   <xsl:apply-templates/>
  </table>
 </xsl:template>
 <xsl:template match="Title">
  <tr>
   <td>
    <!-- display the Author if this is the first element of the group -->
    <xsl:if test="generate-id()=generate-id(key('list',Author))">
     <xsl:apply-templates select="Author"/>
    </xsl:if>
   </td>
   <td>
    <xsl:apply-templates select="Name"/>
   </td>
  </tr>
 </xsl:template>


Hope this helps you. 



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