Hi :)
The following works, but I suspect there is a much simpler way.
<xsl:template match="textdata[(_at_)fileref]">
<xsl:variable name="dir_abs"
select="replace(base-uri(/),'[^\/]+$','')"/>
<!--
AFAICS, basically resolve-uri()
concatenates if @fileref is relative, and
leaves unchanged if it's absolute
-->
<xsl:variable name="file_abs"
select="resolve-uri(@fileref,$dir_abs)"/>
<xsl:copy-of select="unparsed-text($file_abs,'utf-8')"/>
</xsl:template>
<xsl:template match="textobject[textdata[(_at_)fileref]]">
<xsl:apply-templates/>
</xsl:template>
How could I get the base dir of the input ($dir_abs), directly, without
doing replace()?
Tobi
--
http://www.pinkjuice.com/
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list