Jarno,
- thank you very much. The following line of code worked:
<a href="{.}">
<xsl:value-of select="."/>
</a>
Much appreciated.
Brenda
xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com wrote:
<
< Hi,
<
< > <location> http://someserver.ie</location>.
< >
< > I want to retrieve the URL information and display it as a
< > hyperlink in the browser.
< >
< > Currently, I can view the URL information but it is not a hyperlink.
< >
< > I thought of using the following:-
< > <xsl:template match="technical/location">
< > <a href="http://{(_at_)link}"><xsl:value-of select="."/></a>
< > </xsl:template>
< >
< > I will be searching different documents so hardwiring in the
< > URL where it says "@link" would not provide a solution for
< > me. I think that if I could declare a variable in xsl to
< > store the retrieved data and then get at the contents of this
< > variable within the <a href...> tag - this would provide a solution.
<
< <a href="{.}">
< <xsl:value-of select="."/>
< </a>
<
< if the source is as you showed above. If the location of the URL varies, try
something like
<
< <a>
< <xsl:attribute name="href">
< <xsl:choose>
< <xsl:when test="...">
< ...
< </xsl:when>
< ...
< </xsl:choose>
< </xsl:attribute>
< <xsl:value-of select="."/>
< </a>
<
< Cheers,
<
< Jarno - Front Line Assembly: Virus (Counterized Mix)
<
< XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
<
<
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list