Hi,
<location> http://someserver.ie</location>.
I want to retrieve the URL information and display it as a
hyperlink in the browser.
Currently, I can view the URL information but it is not a hyperlink.
I thought of using the following:-
<xsl:template match="technical/location">
<a href="http://{(_at_)link}"><xsl:value-of select="."/></a>
</xsl:template>
I will be searching different documents so hardwiring in the
URL where it says "@link" would not provide a solution for
me. I think that if I could declare a variable in xsl to
store the retrieved data and then get at the contents of this
variable within the <a href...> tag - this would provide a solution.
<a href="{.}">
<xsl:value-of select="."/>
</a>
if the source is as you showed above. If the location of the URL varies, try
something like
<a>
<xsl:attribute name="href">
<xsl:choose>
<xsl:when test="...">
...
</xsl:when>
...
</xsl:choose>
</xsl:attribute>
<xsl:value-of select="."/>
</a>
Cheers,
Jarno - Front Line Assembly: Virus (Counterized Mix)
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list