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Re: how to set the bgcolor of a table cell to the value of an XML attribute

2003-07-18 04:54:29
It looks like you could just do this

<td bgcolor="{Color/@hex}">

Ali Zain Banatwala wrote:
Hi everyone,

  each stock has it's own row and each cell represents
a trading day. i'm trying to set the bgcolor of each
cell to the color(in hex) for that particular node. my
knowledge of XSLT is quite limited and i have no idea
how to do this. i've attached both the xslt file and a
snippet of the xslt file. i'm using Xalan and Xerces
thru JAXP. pls help!

thanks....Zain


  here is a sample of my XML file....

 <Equities-List>
   <Equity name="CP">
     <EquityNode date="2000-01-03" close="9.6">
       <Color hex="246f15">
</EquityNode> <EquityNode date="2000-01-04" close="9.7">
       <Color hex="227017">
</EquityNode> <EquityNode date="2000-01-05" close="9.9">
       <Color hex="1f731a">
</EquityNode> </Equity>
 </Equities-List>


  and here's my XSLT file....

  <xsl:template match="/">
   <html>
    <body>
     <table>
      <xsl:for-each select="//Equity">
       <tr>
<td> <xsl:value-of select="@name"> </td> <td> <xsl:apply-templates select="EquityNode"/> </td> </xsl:for-each>
     </table>
    </body>
   </html>
  </xsl:template>

  <xsl:template match=EquityNode">
    <td bgcolor="<!-- SET COLOR TO @HEX IN COLOR NODE
-->">
      <xsl:value-of select="@date"/>
      <xsl:text> close= </xsl:text>
      <xsl:value-of select="@close"/>
      <br/><br/>
      <xsl:apply-templates select="Color"/>
    </td>
  </xsl:template>

  <xsl:template match=Color">
      <xsl:text> Hex= </xsl:text>
      <xsl:value-of select="@hex"/>
  </xsl:template>


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