You say that each "item" node has three child nodes, yet your list of items
shows four values for each item. Which is correct?
--
Charles Knell
cknell(_at_)onebox(_dot_)com - email
-----Original Message-----
From: "Barak" <barak(_at_)voyager(_dot_)net>
Sent: Thu, 10 Jul 2003 15:43:01 -0400
To: <xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com>
Subject: [xsl] Using not(...a nd ... ) to select nodes
Hello!
I'm fairly new to XSLT and have been trhown in the deep end here. :p
I have a problem I've been beating my head against a wall over for a
couple of days, so now that it's good and bloody I've found this mailing
list.
In a nutshell, I have "item" nodes that have three sub nodes: name, type
and status.
I'm trying to create a node set that only contains different nodes. The
problem I'm running into is I seem to be losing nodes that I shouldn't.
I'm using the following to select the nodes:
<xsl:for-each select="items/item[not(name = preceding-sibling::*/name
and type = preceding-sibling::*/type and status
preceding-sibling::*/status)]">
An example from the XML might be: truck,silverado,chevy,on
truck,silverado,chevy,off truck,ranger,ford,on truck,silverado,chevy,on
truck,silverado,chevy,off
From that I want to see the first three in a node set. However, what
I'm getting are the second and third ones.
Any suggestions would be much appreciated.
Chris
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