Your problem description isn't very clear, but at first sight it looks
as if the problem could easily be solved by doing the numbering in a
second pass, i.e. by creating a result tree and then using it as input
to a second transformation by using xx:node-set().
Michael Kay
-----Original Message-----
From: owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
[mailto:owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com] On Behalf Of
Rajendra S Rawat
Sent: 25 August 2003 11:37
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Incrementing a Global variable
This drawback of XSL/XSL:FO is quite frustating
I want something like this
--------------------------------------
|Sl No | STUDENT NAME | TOption |
--------------------------------------
| 1 | SAM | English | <-
position()=1
--------------------------------------
| 2 | RAJ | English | <-
position()=2
--------------------------------------
| 3 | RON | English | <-
position()=3
--------------------------------------
| 4 | | |
--------------------------------------
| 5 | JON | German | <-
position()=4
--------------------------------------
| 6 | DON | German | <-
position()=5
--------------------------------------
| 7 | | |
--------------------------------------
| 8 | MON | Hebrew | <-
position()=6
--------------------------------------
| 9 | GON | Hebrew | <-
position()=7
--------------------------------------
| 10 | TOTAL= 7 | |
--------------------------------------
| 11 | | |
--------------------------------------
| 12 | | |
--------------------------------------
| 13 | | |
--------------------------------------
| 14 | | |
--------------------------------------
| 15 | | |
--------------------------------------
Pl. Note
1. the rows with out values
2. position() is not same as Sl No.
3. blank rows continues till end of page
4. after first break diff between position() and Sl
No. is 1 (then after second break 2 ....)
5. this is only a very tiny part of xml/output used to
just illustrate the problem, So I cannot use static
sl. no. (it is in a <xsl:for-each select="Student"
..loop)
I have however created above table (breaks by grouping
and extra blank-rows by recursion)
but could not get Sl. No. ordered
I can get something like
--------------------------------------
|Sl No | STUDENT NAME | TOption |
--------------------------------------
| 1 | SAM | English | <-
position()=1
--------------------------------------
| 2 | RAJ | English | <-
position()=2
--------------------------------------
| 3 | RON | English | <-
position()=3
--------------------------------------
| | | |
--------------------------------------
| 4 | JON | German | <-
position()=4
--------------------------------------
| 5 | DON | German | <-
position()=5
--------------------------------------
| | | |
--------------------------------------
| 6 | MON | Hebrew |<- position()=6
--------------------------------------
| 7 | GON | Hebrew |<- position()=7
--------------------------------------
| 10 | TOTAL= 7 | |
--------------------------------------
| 11 | | |
--------------------------------------
| 12 | | |
--------------------------------------
| 13 | | |
--------------------------------------
| 14 | | |
--------------------------------------
| 15 | | |
--------------------------------------
I got last sl no.(10-15) ordered by using
1. break-count(here 2)
2. Student nodes count(here 7)
3. total no. of rows (here 15)(fixed)
Actual Problem is to print Sl No.(Here 1 to 9)
Only solution I suppose, is adding 1,2... after
1st,2nd... breaks but for that I require a global
variable which I can increment and add after every
break.........BUT....in XSL variables are read only!!!!!!!
can anybody show me a way?
(Pl. Also Note Final out put is in PDF.Can it be
achieved with FO .....with backgroud image or Absolute Positioning...
for this problem I also tried ft:assign but failed to
use it
Has any body used ft:assign? )
tia
Regards,
Raj
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