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Re: Selecting "distinct" elements

2003-09-27 00:52:02
This is a simple grouping problem. An efficient solution is using the
Muenchian method for grouping.

Read about it at:
       http://www.topxml.com/code/default.asp?p=3&id=v20010129150851

or at:

       http://jenitennison.com/xslt/grouping/index.html


=====
Cheers,

Dimitre Novatchev.
http://fxsl.sourceforge.net/ -- the home of FXSL



"Marcus Andersson" <marcan(_at_)home(_dot_)se> wrote in message
news:000001c384c6$960ef6e0$0400a8c0(_at_)MarcusNB(_dot_)(_dot_)(_dot_)
Hi
I want to select one of each element with a certain attribute value and
loop over these elements in a for-each (or possibly apply-templates). Is
this possible with a single select statement or do I have to make a more
cumbersome solution? If possible, how would a statement solving the
problem look like?

Instance document:
<root>
 <element value="a"/>
 <element value="b"/>
 <element value="a"/>
 <element value="c"/>
 <element value="b"/>
 <element value="d"/>
 <element value="b"/>
</root>

XSLT Template:
<xsl:template match="root">
 <xsl:for-each select="[insert your favourite statement here]">
  <anotherElt value="{(_at_)value}"/>
 </xsl:for-each>
</xsl:template>

Resulting document:
<root>
 <anotherElt value="a"/>
 <anotherElt value="b"/>
 <anotherElt value="c"/>
 <anotherElt value="d"/>
</root>

Thanks,

/Marcus


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