Hi Marcus,
It seems you need to use xsl:key for grouping. The
Muenchian grouping solution using keys for this
problem is --
<?xml version="1.0"?>
<xsl:stylesheet
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
version="1.0">
<xsl:output method="xml" version="1.0"
encoding="UTF-8" indent="yes"/>
<xsl:key name="x" match="element" use="@value"/>
<xsl:template match="root">
<root>
<xsl:for-each select="element">
<xsl:if test="generate-id(.) =
generate-id(key('x', @value)[1])">
<anotherElt value="{(_at_)value}"/>
</xsl:if>
</xsl:for-each>
</root>
</xsl:template>
</xsl:stylesheet>
Hope I understood the problem correctly..
Regards,
Mukul
--- Marcus Andersson <marcan(_at_)home(_dot_)se> wrote:
Hi
I want to select one of each element with a certain
attribute value and
loop over these elements in a for-each (or possibly
apply-templates). Is
this possible with a single select statement or do I
have to make a more
cumbersome solution? If possible, how would a
statement solving the
problem look like?
Instance document:
<root>
<element value="a"/>
<element value="b"/>
<element value="a"/>
<element value="c"/>
<element value="b"/>
<element value="d"/>
<element value="b"/>
</root>
XSLT Template:
<xsl:template match="root">
<xsl:for-each select="[insert your favourite
statement here]">
<anotherElt value="{(_at_)value}"/>
</xsl:for-each>
</xsl:template>
Resulting document:
<root>
<anotherElt value="a"/>
<anotherElt value="b"/>
<anotherElt value="c"/>
<anotherElt value="d"/>
</root>
Thanks,
/Marcus
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