Re: Count() nodes ??

did u try count(//Root/FixedNodes/Node[(_at_)name=1])


--Rao
On Tuesday, September 16, 2003, at 11:24  AM, 
xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com wrote:
> Hi,
>
> I am having the following xml document.
>
> <Root>
>  <FixedNodes>
>    <Node name="1">
>       <Subnode myAtt="itsValue"/>
>       <Subnode myAtt="itsValue"/>
>       <Subnode myAtt="itsValue"/>
>    </Node>
>    <Node name="2">
>        <Subnode myAtt="itsValue">
>        <Subnode myAtt="itsValue">
>        <Subnode myAtt="itsValue">
>        <Subnode myAtt="itsValue">
>     </Node>
>  </FixedNodes>
>  <VaryingNodes>
>      <Node name="3">
>        <Subnode myAtt="itsValue">
>        <Subnode myAtt="itsValue">
>      </Node>
>   </VaryingNodes>
> </Root>
>
> How do i count number of Subnode within FixedNodes.
> I tried using
>  "count(//Root/FixedNodes/Node/Subnode)
> But i got count as zero. Is this because there is attribute associated
> with
> each of the Node element ?
>
> Can someone please tell me how do i count it ?
> Thanks in the anticipation that I will get some reply.
>
> Regards,
> Dipesh
>
>
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