try
xmlns:java="http://xml.apache.org/xslt/java";
exclude-result-prefixes="java">
in <xsl:stylesheet ...
then use
<xsl:value-of
select="java:format(java:java.text.SimpleDateFormat.new('dd/MM/yyyy'),
java:java.util.Date.new())"/>
to directly print currrent date
Cheers,
Raj
--- logchem(_dot_)news(_at_)zonnet(_dot_)nl wrote:
Hi M.David,
When I use your code, I get the error:
"Error in XPath expression, Function not in
namespace"
Do you know whats wrong?
Thanks,
Peter
Xsl file:
______________________________________________________
<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:fo="http://www.w3.org/1999/XSL/Format";
xmlns:my="urn:my-scripts">
<xsl:output method="html"/>
<xsl:template match="root">
<html><head>
<script type="JavaScript"
implements-prefix="my"><![CDATA[
function returnDate(){
var d, s;
d = new Date();
s += (d.getMonth() + 1) + "/";
s += d.getDate() + "/";
s += d.getYear();
return(s);
}
]]></script>
</head><body>
<xsl:variable name="date"
select="my:returnDate()"/>
<p>Today: <xsl:value-of select="$date"/></p>
</body></html>
</xsl:template>
</xsl:stylesheet>
_____________________________________________________
Xml file:
_____________________________________________________
<?xml version="1.0" encoding="UTF-8"?>
<root>
<naam>Peter</naam>
<datum>2000-08-28T15:39:49</datum>
<dag>28</dag>
<maand>3</maand>
<jaar>2000</jaar>
</root>
______________________________________________________
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