RE: limit count() to nodes with a position() < the postion of the cur

> But I want to take this one step further and return the count 
> of all nodes 
> that have a position() that is less than the position of the 
> current node. 
> Taking the position() of the context node out of the equation 
> I thought it 
> would as simple as this (I used 5 as a test parameter)...
Nodes do not "have a position()". The result of the position() function
is context dependent: it returns the position of the current node in the
current node list, and the current node list depends on how you reached
the node in your processing.

I suspect that you are using "the position of a node" to mean something
like "the number of preceding siblings of the node", which is
count(preceding-sibling::node()).

Michael Kay


> <xsl:key name="linkCount" match="lid[position() &lt; 5]" use="."/>
>
> I expected it to return the count of the nodes that matched 
> the current 
> context node as long as there postion was less than 5.  But 
> it didn't.  It 
> returned the total count for the entire xml tree.
>
> So, my questions are...  1)What do I need to change to get 
> the above example 
> to work and 2)How could I then take it one step further and use the 
> position() of the current context node as the parameter to 
> test against the 
> position() of the test nodes?
>
> Your help is much appreciated!
>
> Best Regards,
>
> M.David 
>
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list