Re: Handling Duplicate Lines in XSL

Heres a quick fix to your grouping problem...

If the XML was in the following format...

<foo>
    <bar>Cust1 443 West</bar>
    <bar>Cust1 443 West</bar>
    <bar>Cust1 443 West</bar>
    <bar>Cust1 443 East</bar>
</foo>

the following XSL will test to see if the current node is equal to any of
the preceding elements and if it is it will not include it in the resulting
node-set.  It then prints the value of each node.  So this...

<xsl:for-each select="foo/bar[not(. = preceding-sibling::bar)]">

    <xsl:value-of select="."/><br/>

</xsl:for-each>

Will produce this...

Cust1 443 West
Cust1 443 East

Best of luck,

M.



----- Original Message ----- 
From: "Jens Serna" <jserna(_at_)simonspetroleum(_dot_)com>
To: <XSL-List(_at_)lists(_dot_)mulberrytech(_dot_)com>
Sent: Wednesday, October 29, 2003 3:00 PM
Subject: [xsl] Handling Duplicate Lines in XSL


> I have an XML file with multiple rows which are the same:
>
> Cust1 443 West
> Cust1 443 West
> Cust1 443 West
>
> Is there any way to suppress the second or third row if it is the same as
the previous one?
> At first I tried using variables, but then I found that you can't change
variable values.
> <xsl:variable name="newcust" select="CUST"/>
> <xsl:variable name="cust"/>
> <xsl:if test="$cust!=$newcust">
>
> Is there another way?
>
> Thanks,
>
> Jens
>
>  XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list

 XSL-List info and archive:  http://www.mulberrytech.com/xsl/xsl-list