The code you've shown us looks fine.
This probably means the bug is in the code you haven't shown us.
Michael Kay
-----Original Message-----
From: owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
[mailto:owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com] On Behalf Of
Mark Ivs
Sent: 24 October 2003 16:57
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] xsl variable - issue
Hello,
Please take a look at the XML and XSL files. I have
variable called contentsVar which contains a node set.
For some reason, the 'if' statement is failing though
the XML says isvisible = true. Not sure what I am
doing wrong.
Any help will be appreciated.
Thanks.
XML:
<root>
<book>
<contents isvisible="true">
<chap>
<chap>
</contents>
</book>
</root>
XSL:
<xsl:template match="book">
<xsl:variable name="contentsVar" select="contents"/>
.
.
.
<xsl:if test="$contentsVar/@isvisible = 'true'">
do something...
</xsl:if>
</xsl:template>
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