You're looking for the xx:evaluate() function which is defined in EXSLT
and is available in a number of popular processors. Though the specs are
likely to vary slightly in terms of the context for evaluating the
expression, e.g. whether it allows variables or not.
Michael Kay
-----Original Message-----
From: owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
[mailto:owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com] On Behalf Of
Anderson, Rick A
Sent: 21 October 2003 17:03
To: 'XSL-List(_at_)lists(_dot_)mulberrytech(_dot_)com'
Subject: [xsl] Generating an Xpath expression dynamically
Hi,
I am trying to use XSLT to transform a set of XML files, each type
with its own set of nodes, into a legacy file format. It is best if
the XSLT was generic. I've tried to reference a second XML
file that
contains the transformation rules. This second XML file
contains the
relative XPath expression for each element in the source
XML file and
the target location in the legacy file format. I get the relative
XPath string from the second XML file into a parameter, but
when I try
to use that parameter in a XSLT value-of element, it outputs the
relative XPath string rather than the contents of that node in the
source XML file.
Does anyone know how to output the contents of an element node in a
source XML file using a XPath string read in from another XML file?
Thanks.
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list