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RE: Regarding xsl transformation to xml tree

2003-10-08 14:15:46

I am in a quandary. I have a huge xml tree that has the 
following structure-

Firstly, this is a bad XML design. Mixed content should not normally be
used for data-oriented XML. It would be much better to use:

        <plant species="maple">
                <type>tree</tree>
                <height>tall</height>
        </plant>

or

        <plant>
            <species>maple</species>
                <type>tree</tree>
                <height>tall</height>
        </plant>

But if you can't change it, then use

<xsl:template match="plant">
        <tr><td><value-of select="normalize-space(text())"/></td></tr>
</xsl:template>

to extract the child text node without getting all the descendant text
nodes.

Michael Kay


 

<all_plants>

      <plant> maple
              <type>tree</tree>
              <height>tall</height>
      </plant>

      <plant> dandelion
              <type>weed</tree>
              <height>short</height>
      </plant>

      <plant> sage
              <type>herb</tree>
              <height>short</height>
      </plant>

</all_plants>

I need the xsl that would give me a result as:

Maple
Dandelion
Sage

Here is the XSL transform I am using

<xsl:template match="/">
      <html>
              <body>
                      <xsl:apply-templates select="all_plants">
              </body>
      </html>
</xsl:template>

<xsl:template match="all_plants">
      <table>
              <xsl:apply-templates select="plant">
      </table>
</xsl:apply-templates>

<xsl:template match="plant">
      <tr><td><value-of select="."/></td></tr>
</xsl:template>


....let me know what I am doing wrong!!
Is there any other way I can do this?????

Any help would be greatly appreciated...

Regards,
DC


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