Abhijit,
That is giving me no result. I need to select
Maple
Dandelion
Sage
To make it clear...I DO NOT have the option to change the xml.
-----Original Message-----
From: Abhijit Junnare [mailto:mavlaabhi(_at_)yahoo(_dot_)com]
Sent: Wednesday, October 08, 2003 3:59 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] Regarding xsl transformation to xml tree
--- "Chadha, Devesh" <devesh(_dot_)chadha(_at_)lehman(_dot_)com> wrote:
Hi,
I am in a quandary. I have a huge xml tree that has
the following structure-
<all_plants>
<plant> maple
<type>tree</tree>
<height>tall</height>
</plant>
<plant> dandelion
<type>weed</tree>
<height>short</height>
</plant>
<plant> sage
<type>herb</tree>
<height>short</height>
</plant>
</all_plants>
I need the xsl that would give me a result as:
Maple
Dandelion
Sage
Here is the XSL transform I am using
<xsl:template match="/">
<html>
<body>
<xsl:apply-templates select="all_plants">
</body>
</html>
</xsl:template>
<xsl:template match="all_plants">
<table>
<xsl:apply-templates select="plant">
</table>
</xsl:apply-templates>
<xsl:template match="plant">
<tr><td><value-of select="."/></td></tr>
</xsl:template>
This will get you all the text that is inside the
plant element and its children I guess.
....let me know what I am doing wrong!!
Is there any other way I can do this?????
Instead do the following
<xsl:template match="plant">
<tr><td><xsl:apply-templates/>td></tr>
</xsl:template>
<xsl:template match="type">
</xsl:template>
<xsl:template match="height">
</xsl:template>
Any help would be greatly appreciated...
Regards,
DC
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complete or accurate and it should not be relied upon as such. All
information is subject to change without notice.
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list