I thought the were going to be equal because they are part of the same
context. Is there a way to compare the pair-wise unequal $unique-rooms to
say an a sibling node with similar data? Is context part of the select
statement? If I select //topics/topic/location am I in the location
context, if so can I compare "." to //topics/place/room data? If not,
please explain or send some keywords about my learning deficits so I may
be engoogled.
Jeff
owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com wrote on 11/25/2003
04:21:59 PM:
jderbyshire(_at_)caicorp(_dot_)com wrote:
<topics>
<topic>
<name>Introduction to LotusScript for Lotus Notes and Domino</name>
<start>0800</start>
<end>1000</end>
<location>SW 1-4</location>
</topic>
...
<xsl:variable name="unique-rooms"
select="//topics/topic/location[not(. =
preceding::location)]" />
...
<xsl:for-each select="$unique-rooms">
...
<xsl:if test=". = ../location">
...
I don't understand
why the xsl:if is always true if I am comparing 2 different things,
You compare two equal things. The $unique-rooms is a set of all
location
elements which are pairwise unequal. The context node for the test
expression is such an location element. The parent of this node has
exactly
one location element as child, the element which is also the context
node.
Therefore both . and ../location resolve to the same node, no surprise
that
the comparision of their contents is always true.
J.Pietschmann
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