I've just figured this out... spurred on by the embarrassment of having to
ask it in public ;-):
Can someone please post a small XSLT stylesheet that outputs a result tree
containing an xmlns attribute on the root element, similar to this?
I was "trying too hard" on my previous attempts. All it took was an
exclude-result-prefixes, and a simple xmlns attribute in the template. Doh!
<?xml version='1.0'?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:html="http://www.w3.org/1999/xhtml";
exclude-result-prefixes="html">
<xsl:output method="xml" version="1.0" indent="yes"
omit-xml-declaration="yes"/>
<xsl:template match="/">
<html xmlns="http://www.w3.org/1999/xhtml";>
<head/>
<body>
<ul>
<li>Any XHTML elements</li>
</ul>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list