Can someone please post a small XSLT stylesheet that outputs a result tree
containing an xmlns attribute on the root element, similar to this?
<html xmlns="http://www.w3.org/1999/xhtml">
<head/>
<body>
<ul>
<li>Any XHTML elements</li>
</ul>
</body>
</html>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<html xmlns="http://www.w3.org/1999/xhtml">
<head/>
<body>
<ul>
<li>Any XHTML elements</li>
</ul>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
or more commonly, and usefully if you have more than one template:
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
xmlns="http://www.w3.org/1999/xhtml">
<xsl:template match="/">
<html>
<head/>
<body>
<ul>
<li>Any XHTML elements</li>
</ul>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
David
--
http://www.dcarlisle.demon.co.uk/matthew
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