Yes you are absolutely right I had a wrong idea of the problem.
Here is a complete XML sample:
************************************
<dump>
<identification>
<version>1.0</version>
<date>17/04/2003</date>
</identification>
<data>
<project eiac="PISCINE">
<eiac>PISCINE</eiac>
<lotnum>Lot 1</lotnum>
<contractnum>0011</contractnum>
<lcnstructure>11222333</lcnstructure>
<projectpricecoef>0.000</projectpricecoef>
<projectpricecur>EUR</projectpricecur>
<totalsystems>1</totalsystems>
<xafree1>REF LSA</xafree1>
<xafree2>Rev</xafree2>
<xafree10>ED1</xafree10>
</project>
<breakdown eiac="PISCINE" lcn="P1AA00XX" alc="00">
<action>delete</action>
<eiac>PISCINE</eiac>
<lcn>P1AA00XX</lcn>
<alc>00</alc>
<lcntype>P</lcntype>
<uoc1>PS1</uoc1>
<xbfree1>ED1</xbfree1>
<xbfree2>E</xbfree2>
</breakdown>
<breakdown eiac="PISCINE" lcn="P1AA00XX001" alc="00">
<action>delete</action>
<eiac>PISCINE</eiac>
<lcn>P1AA00XX001</lcn>
<alc>00</alc>
<lcntype>P</lcntype>
<breakramind>Y</breakramind>
<uoc1>PS1</uoc1>
<uoc2>PS2</uoc2>
<xbfree1>ED1</xbfree1>
<xbfree2>F</xbfree2>
</breakdown>
<breakdown eiac="PISCINE" lcn="P1AA01AB" alc="01">
<action>delete</action>
<eiac>PISCINE</eiac>
<lcn>P1AA01AB</lcn>
<alc>01</alc>
<lcntype>P</lcntype>
<breakramind>Y</breakramind>
<uoc1>PS2</uoc1>
<xbfree1>ED1</xbfree1>
<xbfree2>E</xbfree2>
</breakdown>
<breakdownlanguage eiac="PISCINE" lcn="P1AA00" alc="01" language="FR">
<eiac>PISCINE</eiac>
<lcn>P1AA00</lcn>
<alc>01</alc>
<lcntypexb1>P</lcntypexb1>
<language>FR</language>
<lcnnom>S_SYST FILTRATION</lcnnom>
<lcnnomfull>S_SYST FILTRATION</lcnnomfull>
</breakdownlanguage>
<breakdownlanguage eiac="PISCINE" lcn="P1AA00XX003" alc="01"
language="FR">
<action>delete</action>
<eiac>PISCINE</eiac>
<lcn>P1AA00XX003</lcn>
<alc>01</alc>
<lcntypexb1>P</lcntypexb1>
<language>FR</language>
</breakdownlanguage>
<breakdownlanguage eiac="PISCINE" lcn="P1AA00XX" alc="00" language="EN">
<action>delete</action>
<eiac>PISCINE</eiac>
<lcn>P1AA00XX</lcn>
<alc>00</alc>
<lcntypexb1>P</lcntypexb1>
<language>EN</language>
<lcnnom>ALIMENTATION EAUX</lcnnom>
<lcnnomfull>ALIMENTATION EAUX</lcnnomfull>
</breakdownlanguage>
</data>
</dump>
********************************************************
Usually my input XML files are much bigger but this one is a good example.
The <action> elements all have the value "delete" but this is not a problem.
There are two groups (I'm only interested in the children of <data> that have
<action> elements): breakdown and breakdownlanguage.
I repeat that I need, for each of both groups, to build an HTML table. To set
the headers of those tables, I must get all possible children of a category (the
children differ from one member of a group to another, but a member has only one
child of a certain kind). Then the tables are filled with the textnode values of
those children (a field can be blank if there is no child of a certain
category).
(But then, in a way, I must pay attention to the order of the headers).
If someone could show me how nested grouping works, using the Muenchian
method...
Thanks in advance,
Jean
Dimitre Novatchev a écrit :
I group elements that have an <action> child by name and then for each
group I
build an HTML table. Members of the same group usually have the same set
of
childnodes, but this is not always the case, and this is a problem, given
the
way I build the tables: I get the first member of the group and set the
headers of the table to the names of its children (<th align="center"
bgColor="lightgrey"><xsl:value-of select="name()"/> </th>). When other
members
of the group have more children, the values of those latter are put in a
new
column without header...
So, instead of getting the first member of the group, I would like to get
the
one with the greatest number of children (to get all the headers, it's not
a
problem if some fields are blank in the table). Is this possible?
This is possible, but you have a wrong idea about the problem. Even if you
use the element with biggest number of children, there might be other
elements in the same group that have children, whose name will not be
represented in the column header.
What you really need is all different names of all children of all elements
in a group.
This is nested grouping and has a standard solution using the same Muenchian
method.
Please, give a minimal complete example of a source xml document and many
people in this group will be glad to provide the solution.
=====
Cheers,
Dimitre Novatchev.
http://fxsl.sourceforge.net/ -- the home of FXSL
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list