I suspect that you didn't only add the xsi:schemaLocation, you also
added the default namespace declaration. Changing the namespace of the
elements in your source document will typically mean that none of the
template rules in your stylesheet match any more.
Michael Kay
-----Original Message-----
From: owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
[mailto:owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com] On Behalf Of
davidpbrown
Sent: 27 January 2004 23:00
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] No html if XSD present?
I have an XML source from which I generate xhtml from an XSLT.
That works fine and there's no problem until I suggest a XSD
in the XML. Then it spews out only the text result with none
of the tags!?
The only tag to survive is the XML <?xml version="1.0"
encoding="utf-8"?>
The XSL, XSD and XML are all valid as per the Sun's
Multischema XML validator (thanks to G. Ken Holman for
suggesting that in another post)
The XML's XSD declaration I have as
<file xmlns="http://www.example.com/ns/file.xsd";
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance";
xsi:schemaLocation="http://www.example.com/ns/file.xsd";>
I am processing these on my local hard drive but this seems
to be ok, in that the XSD declares that it is the
http://www.example.com/ns/file.xsd
suggested, even though it isn't found at that location.
The command line used is
java org.apache.xalan.xslt.Process -in file.xml -xsl file.xsl -out
file.html
Any ideas why no tags pass when XSD is present?
Thanks
davidpbrown
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