Hi Ricardo,
From what I understand, your problem seems to be same as mine: Please check
my posting today: Linear counting problem in nested loop.
I guess you have a nested loop within a loop (just like I have and you need
to set the ids as a linear counter value). I am in the same boat if I
understood you right. Good Luck. I hope someone out there (XSL Guru) may be
able to solve our issues.
Anoop
-----Original Message-----
From: Ricardo Saraiva [mailto:rss(_at_)dee(_dot_)fct(_dot_)unl(_dot_)pt]
Sent: Thursday, January 22, 2004 12:47 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: [xsl] increment value
Hi,
That was an example. The numbers were not to be added to the
string.
Imagine the example without the numbers.
How do I increment a variable to add to the string?
Thanks,
Ricardo Saraiva
-----Original Message-----
From: owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
[mailto:owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com] On Behalf Of
Andreas L.
Delmelle
Sent: quinta-feira, 22 de Janeiro de 2004 17:16
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: [xsl] increment value
-----Original Message-----
From: Ricardo Saraiva
<snip />
<a>
<b>1</b>
<b>2</b>
</a>
<a>
<b>3</b>
<b>4</b>
</a>
The output would be:
<b id="b1"/>
<b id="b2"/>
<b id="b3"/>
<b id="b4"/>
.
Something like:
<xsl:template match="a/b">
<xsl:element name="b">
<xsl:attribute name="id">
<xsl:value-of select="concat(name(.),.)" />
</xsl:attribute>
</xsl:element>
</xsl:template>
Cheers,
Andreas
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list