This solution doesnt appear to work with xalan? (namespace
xmlns:xx="http://exslt.org/common")
however, it does work with xmlns:xx="urn:schemas-microsoft-com:xslt" are
there any small tweaks that i have to do in order to make it work?
cheers
james
From: David Carlisle <davidc(_at_)nag(_dot_)co(_dot_)uk>
Reply-To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] sorting information from multiple files
Date: Thu, 15 Jan 2004 16:23:03 GMT
document() will accept a node set rather than a string so if it wasn't
for the " " "-" translation you could replace
<xsl:for-each select="child::category">
<xsl:variable name="catnamemod" select="translate(name,' ','_')" />
<xsl:for-each
select="document($nsindex/*[name()=$catnamemod])/root/child::*">
<xsl:if test="@topfive=true()">
by
<xsl:for-each
select="document($nsindex/*[name()=current()/category/name])/root/child::*[(_at_)topfive]">
Is it not possible to arrange that your nsindex variable has the right
names
(by doing the translation at the point you construct that variable?
it's inconvenient to do the translation later as that is a string based
function which stops you using the implicit existential quantification
over a node set that you get with =.
--
http://www.dcarlisle.demon.co.uk/matthew
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