Something like this:
<?xml version="1.0"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:template match="/">
<xsl:for-each select="//VehInfo[descendant::UsageInfoCode =
'Work']">
<xsl:element name="VehInfo">
<xsl:element name="ModelYear">
<xsl:value-of select="ModelYear"/>
</xsl:element>
<xsl:element name="Model">
<xsl:value-of select="Model"/>
</xsl:element>
</xsl:element>
</xsl:for-each>
</xsl:template>
</xsl:stylesheet>
-----Original Message-----
From: owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
[mailto:owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com] On Behalf Of
Gary Fix
Sent: Wednesday, February 25, 2004 10:17 AM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] How Do I Select A Section of XML Based On A Code Value
Hi,
I have an xml something like this:
<VehInfo>
<ModelYear>2004</ModelYear>
<Model>Ford</Model>
<UsageInfo>
<UsageInfoCode>Work</UsageInfoCode>
</UsageInfo>
</VehInfo>
<VehInfo>
<ModelYear>1994</ModelYear>
<Model>Toyota</Model>
<UsageInfo>
<UsageInfoCode>Pleasure</UsageInfoCode>
</UsageInfo>
</VehInfo>
and want to transform this into xml using xsl, selecting the correct section
based on the <UsageInfoCode> tag. For example, if I am to select using an
"UsageInfoCode" of "Work", then I want the output xml to look like this:
<VehInfo>
<ModelYear>2004</ModelYear>
<Model>Ford</Model>
</VehInfo>
Any help would be greatly appreciated!
thanks....gary...
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