It seems that you're not passing the correct ID param
value or not setting the ID param value at all...
I tryed:
xsltproc --stringparam ID U-05585 b.xsl a.xml
and the result is /users/local/u/john
as you expected.
Rui
On Wed, 2004-02-18 at 16:00, Aitor San Juan wrote:
Hello all,
I'm stuck with simple XSL transformation. I just want to get the "home"
directory of a user given his ID (a unique code). Trying this transformation
with user id "U-05585", I always get the value "/users/local/u" and it
should be "/users/local/u/john".
Can anybody help me? What am I doing wrong or missing?
Thanks in advance.
My XSL file:
===================================
<?xml version="1.0" encoding="ISO-8859-1"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
version="1.0">
<xsl:param name="ID"/>
<xsl:output method="text" indent="no" omit-xml-declaration="yes"
encoding="ISO-8859-1"/>
<xsl:strip-space elements="*"/>
<xsl:template match="/">
<xsl:value-of
select="concat(/users/@dirbase,/users/user[(_at_)id=$ID]/home)"/>
</xsl:template>
</xsl:stylesheet>
My INPUT file:
===================================
<?xml version="1.0" encoding="ISO-8859-1"?>
<users dirbase="/users/local/u">
<user id="U-05585">
<name>User Name 1</name>
<home>/john</home>
</user>
</users>
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Rui Alberto L. Gonçalves <rui-l-goncalves(_at_)ptinovacao(_dot_)pt>
PT Inovação
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