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RE: Value at position()

2004-02-03 10:49:07
Here is the xml example..

<lomp>
  <location path="..\..\..\..\..\">040202</location> 
  <location path="..\..\..\..\">Socio Acto</location> 
  <location path="..\..\..\">Dossoro</location> 
  <location path="..\..\">A</location> 
  <location path="..\">Mentol</location> 
  <location last="true" path="">Lentils</location> 
</lomp>

By the way, I have tried the following but still no success since it
always return the value of first position (040202)!

                <xsl:variable name="doc_cat">
                <xsl:for-each select="cat">
<xsl:choose>
                <xsl:when test="(position()=last()-2='A') or
(position()=last()-2='B')  or (position()=last()-2='C')">

        <xsl:variable name="doc_cat2">
                        <xsl:value-of select="position()"/>
        </xsl:variable>

                <xsl:value-of select="//lomp/location['$doc_cat2']"/>

                </xsl:when>
</xsl:choose>
                </xsl:for-each>
                </xsl:variable>


Regards,


-----Original Message-----
From: SHEIKH Sajjad 
Sent: 03 February 2004 18:02
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Value at position()


Hi all,

A little issue, which I am unable to resolve.

I am matching my cat against value A, B and C at position()=last()-2.  
If it finds it, it displays that positioned value.  In the following
example, I expect the value of position()=last()-2 only.

Any suggestions?
Regards,


                <xsl:variable name="doc_cat">
                <xsl:for-each select="cat">
<xsl:choose>
                <xsl:when test="(position()=last()-2='A') or
(position()=last()-2='B')  or (position()=last()-2='C')">
                        <xsl:value-of select="."/>
                </xsl:when>
</xsl:choose>
                </xsl:for-each>
                </xsl:variable>


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