OK
I have understand..
But I must show extract because my XSL and my XML are very large..
My XSL:
<body>
<table border="1">
<tr>
<td>
<xsl:apply-templates
select="/tim/Tache_struct"></xsl:apply-templates>
<xsl:apply-templates
select="/tim/Tache_struct/Tache_atomique"></xsl:apply-templates>
<xsl:apply-templates
select="/tim/Tache_struct/Tache_struct"></xsl:apply-templates>
</td>
</tr>
</table>
</body>
My XML:
<tim>
<Tache_struct>
<Tache_atomique></Tache_atomique>
<Tache_atomique></Tache_atomique>
<Tache_atomique></Tache_atomique>
<Tache_struct></Tache_struct>
<Tache_struct></Tache_struct>
<Tache_atomique></Tache_atomique>
</Tache_struct>
</tim>
Actually after the transforamtion i have this result :
<tim>
<Tache_struct>
<Tache_atomique></Tache_atomique>
<Tache_atomique></Tache_atomique>
<Tache_atomique></Tache_atomique>
<Tache_atomique></Tache_atomique>
<Tache_struct></Tache_struct>
<Tache_struct></Tache_struct>
</Tache_struct>
</tim>
I try to use <XSL:sort> in add an attribute at each Tache_struct and each
Tache_atomique
But the result is the same.
Anybody has a solution to keep the same order of the tag after the
transformation?
Thanks :)
-----Original Message-----
From: Andrew Welch [mailto:AWelch(_at_)piper-group(_dot_)com]
Sent: Wednesday, March 31, 2004 11:48 AM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: [xsl] Problems with a right order display of tags
Yes i know that, i haven't use the good syntax in the mail
But I know all the right syntax!!
I want a solution more "subjective"
Please :)
But what is this?
<xsl :call-templates match= /A >
It is neither
<xsl:template match="/A"/>
<xsl:call-template name="A"/>
Or
<xsl:apply-templates select="/A"/>
If you know all the right syntax then use it! No one can guess from
your made up syntax what you are asking...
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