Hi,
<xsl :call-templates match= /A >
is not valid XSLT.
Take a look at http://www.mulberrytech.com/quickref/index.html for the syntax.
Another good url to get started is: http://www.dpawson.co.uk/xsl/index.html
Cheers,
Agnes
-----Original Message-----
From: Bertrand Sauviat [mailto:bsauviat(_at_)elanspeech(_dot_)com]
Sent: woensdag 31 maart 2004 10:52
To: 'xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com'
Subject: [xsl] Problems with a right order display of tags
Hello,
I want display the contents of my XML document with an XSL stylesheet in the
order of the XML document
My Xml here :
<A>
<B></B>
<B></B>
<B></B>
<C></C>
<C></C>
<B></B>
</A>
My XSL here (extract) :
<body>
<xsl :call-templates match= /A >
<xsl :call-templates match= /A/B >
<xsl :call-templates match= /A/C >
</body>
For each template I have some instructions but the problem isn't here..
After the transformation, In output I have :
<A>
<B></B>
<B></B>
<B></B>
<B></B>
<C></C>
<C></C>
</A>
Is it possible to keep the order of the XML document after the
transformation.
There is no distinction between <B> and <C>
Thanks for help
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