hi,
do i understand your intention as:
- give any of the 3 links an URL parameter that should then be passed to the
XSL like
<a><xsl:attribute>
name="href">test.xml?evaluate=admin</xsl:attribute>evaluate the admin</a></p>
- XSL should then display only relevant data on the URL parameter?
chris
-----Ursprüngliche Nachricht-----
Von: Markus Hanel [mailto:markus(_dot_)hanel(_at_)gmx(_dot_)at]
Gesendet: Dienstag, 30. März 2004 13:24
An: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Betreff: Re: AW: [xsl] change a attribute with a link?
hello,
the 3 links and the template " <xsl:template
match="node[attribute::type =
'admin']">
" are in one stylesheet. the links should evaluate the same
xml file and
there should be a possibility (I hope so) to change the
attribute "type" at the
xslt element " apply-templates and template". is there a xslt
element or x
path function that can transport a parameter that is given at a link?
So when I change the attribute "type" to interviewer all
pers_datas of the
<node type="department">
should be catched.
do you want to open the link with a parameter which type of
pers_data you
want to show or is this all on one file?
in case of the parameter you need to provide information
which environment
you work in (servlet?)
if you want to put it all in one file you could do something like:
<xsl:template match="/">
<!-- this is slow, better to select the proper nesting
if possible -->
<xsl:apply-templates select="//pers-data"/>
</xsl:template>
<xsl:template match="pers_data">
<p>
<!-- @ is the same as attribute:: but i think
much neater cause it is
shorter -->
<a href="test.xml?param={parent::node/@type}">
<xsl:value-of select="parent::node/@type"/>
</a>
</p>
</xsl:template>
is that what you were trying to do?
chris
-----Ursprüngliche Nachricht-----
Von: Markus Hanel [mailto:markus(_dot_)hanel(_at_)gmx(_dot_)at]
Gesendet: Dienstag, 30. März 2004 10:21
An: xsl mailinglist
Betreff: [xsl] change a attribute with a link?
hello,
I want to list some informations of pers_datas of some nodes.
The routine is
equal for the attribut "admin", "interviewees" and
"interviewer" of this
nodes. My idear is to make 3 links, every link opens the same
file and evaluates
with one of the attributes: admin, interviewees or
interviewer. Therefore I
had to change the value of "attribute::type" of the xslt elements:
apply-templates and template. Is there a possibility to
arange this?
xml file
<node type="admin">
<pers_data></pers_data>
<node type="school">
<node type="interviewees">
<pers_data></pers_data>
<pers_data></pers_data>
<pers_data></pers_data>
</node>
<node type="department">
<node type="interviewer">
<pers_data></pers_data>
<pers_data></pers_data>
<pers_data></pers_data>
</node>
...
xsl file
<xsl:stylesheet>
...
<p><a><xsl:attribute
name="href">test.xml</xsl:attribute>evaluate the
admin</a></p>
<p><a><xsl:attribute
name="href">test.xml</xsl:attribute>evaluate the
interviewees</a></p>
<p><a><xsl:attribute
name="href">test.xml</xsl:attribute>evaluate the
interviewer</a></p>
...
<xsl:apply-templates
select="descendant-or-self::node[attribute::type =
'admin']" />
....................................should change to
[attribute::type =
'interviewees']
<xsl:template match="node[attribute::type = 'admin']">
...
</xsl:template>
</xsl:stylesheet>
Many thanks
markus
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