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Re: Problem writing xsl to convert xml to excel

2004-03-05 16:10:42

printed from column1 instead of column0.
use position() -1 instead of position(), but you are making it far
more complicated than it need be


For example

    <xsl:for-each select="row">
        
      <xsl:apply-templates select=".">
        <xsl:with-param name="rownumber" select="position()"/>
      </xsl:apply-templates>
    </xsl:for-each>



could just be
<xsl:apply-templates select="row"/>

then your row template just needs to be

  <xsl:template match="row">
    <xsl:variable name="rownumber" select="position()">

...




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