Thanks David, I had already notice the "mistake" and i'm trying to complete
my code with this idea. But it's a little hard because my code is more
complex than my sample example on this list. I mean the concept is the same
but theres many kinds of count to do and many lines and... so i hope i'll
make it right soon !
PS : you were right, never say there's no solution... there's always one but
i don't always see it. As would say the schadocks (an old french cartoon) :
"If there's no solution, than there is no problem !" :)
-----Message d'origine-----
De : owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
[mailto:owner-xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com]De la part de
David
Carlisle
Envoyé : jeudi 4 mars 2004 15:36
À : xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Objet : Re: [xsl] reccursive sum ?
so you just want to sum that:
<xsl:value-of select="msxsl:node-set($ME-sum)/sum"/>
or rather:
<xsl:value-of select="sum(msxsl:node-set($ME-sum)/sum)"/>
--
http://www.dcarlisle.demon.co.uk/matthew
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