Thanks a lot. That was exactly what I wanted (and it works, too).
-----Original Message-----
From: Mukul Gandhi [mailto:mukulgandhi2003(_at_)yahoo(_dot_)co(_dot_)in]
Sent: Dienstag, 6. April 2004 17:49
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] Dynamical work with child nodes
Hi Roland,
Something like the following might be ok. The
structure just illustrates the concept.
<xsl:template match="/">
<xsl:for-each select="root/rowset/row">
<xsl:for-each select="*">
<xsl:value-of select="name(.)" /> -
<xsl:value-of select="." />
</xsl:for-each>
</xsl:for-each>
</xsl:template>
Regards,
Mukul
--- Roland Juergens <roland_juergens(_at_)icon-scm(_dot_)com>
wrote: > Hi,
I have an XML file like this which contains results
from a database query.
Is there a way to go dynamically through the
subelements of my "row"
elements, because I want to use it for different
queries.
So the subelements like "id" or "name" might change.
<root>
<rowset>
<row>
<id>1</id>
<name>bla</name>
</row>
<row>
<id>2</id>
<name>blabla</name>
</row>
...(more <row> elements)...
</rowset>
</root>
This is how the xsl-file looks like now
...
<xsl:for-each select="root/rowset/row">
...
<xsl:value-of select="id"/>
...
<xsl:value-of select="name"/>
...
</xsl:for-each>
...
What I imagine is the following :
I want to get the number of subelements of a "row"
element, then iterate
over it to get the names, and then building it
dynamical.
Is something like that possible ?
Roland Juergens
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