You can do it this way, but you need to display a different node each time,
so you presumably want something like
<xsl:value-of select="data/objekt/filename[$count+1]"/>
However, you really don't need recursion for this. Just
<xsl:for-each select="data/objekt/filename">
<xsl:if test="position() mod 3 = 0">..</xsl:if>
Michael Kay
-----Original Message-----
From: Peter Lukan [mailto:peter(_dot_)lukan(_at_)email(_dot_)si]
Sent: 01 April 2004 10:04
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Display records in 3 columns
Hello!
I'm having trouble with displaying data in 3 columns.
I've managed to create a table with 3 columns :
******* XSL code ***********
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
version="1.0">
<xsl:output method="html"/>
<xsl:template match="/">
<table width="400">
<xsl:call-template name="coloredRow">
<xsl:with-param name="count" select="1"/>
</xsl:call-template>
</table>
</xsl:template>
<xsl:template name="coloredRow">
<xsl:param name="count"/>
<xsl:if test="$count != count(data/objekt)">
<xsl:if test="1=($count mod 3)">#<#tr#>#</xsl:if>
<td bgcolor="#ccff66">
vsebina: <xsl:value-of select="data/objekt/filename"/>
</td>
<xsl:if test="0=($count mod 3)">#<#/tr#>#</xsl:if>
<xsl:call-template name="coloredRow">
<xsl:with-param name="count" select="$count + 1"/>
</xsl:call-template>
</xsl:if>
</xsl:template>
</xsl:stylesheet>
************* end of XSL code **************
but I can't display different records in this code <xsl:value-of
select="data/objekt/filename"/>
I think I should use position() function but don't know how!
Thanx Peter Lukan
--+------------------------------------------------------------------
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail:
<mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--+--