Write an identity template that copies everything:
<xsl:template match="node()|@*">
<xsl:copy>
<xsl:apply-templates select="node()|@*"/>
</xsl:copy>
</xsl:template>
Then override it for the things you want to change:
<xsl:template match="a/@ID">
<xsl:attribute name="ID">0</xsl:attribute>
</xsl:template>
Michael Kay
-----Original Message-----
From: Kenny Akridge [mailto:kenny(_at_)akridgefamily(_dot_)com]
Sent: 14 May 2004 13:16
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] Small changes to source XML
Forgive me for seeming ignorant, but I certainly am in this
case. I want to
mostly copy all of my source XML to the output XML, with some
small changes.
For instance:
<root>
<a ID="74">
<a ID="75">
<a ID="76">
</root>
I want this output:
<root>
<a ID="0">
<a ID="0">
<a ID="0">
</root>
What is the best way to do this with a lot of XML without
using xsl:element?
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