At 2004-05-14 09:16 -0400, Kenny Akridge wrote:
I want to
mostly copy all of my source XML to the output XML, with some small changes.
...
What is the best way to do this with a lot of XML without using xsl:element?
Use an identity transform with additional template rules ... I used your
data in the example below to produce your desired result.
I hope this helps.
............... Ken
T:\ftemp>type kenny.xml
<root>
<a ID="74"/>
<a ID="75"/>
<a ID="76"/>
</root>
T:\ftemp>type kenny.xsl
<?xml version="1.0" encoding="iso-8859-1"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
version="1.0">
<xsl:template match="a/@ID">
<xsl:attribute name="ID">0</xsl:attribute>
</xsl:template>
<xsl:template match="@*|node()"><!--identity for all other nodes-->
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
T:\ftemp>saxon kenny.xml kenny.xsl
<?xml version="1.0" encoding="utf-8"?><root>
<a ID="0"/>
<a ID="0"/>
<a ID="0"/>
</root>
T:\ftemp>
--
Public courses: Spring 2004 world tour of hands-on XSL instruction
Next: 3-day XSLT/XPath; 2-day XSL-FO - Birmingham, UK June 14,2004
World-wide on-site corporate, govt. & user group XML/XSL training.
G. Ken Holman mailto:gkholman(_at_)CraneSoftwrights(_dot_)com
Crane Softwrights Ltd. http://www.CraneSoftwrights.com/s/
Box 266, Kars, Ontario CANADA K0A-2E0 +1(613)489-0999 (F:-0995)
Male Breast Cancer Awareness http://www.CraneSoftwrights.com/s/bc
Legal business disclaimers: http://www.CraneSoftwrights.com/legal