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RE: two namespaces and a position problem

2004-05-13 08:15:18
Well here' the deal.  I want to do that because my first namespace contains
a schema and the second is my data.  The first namespace has elements
AttributeType for each attribute contained in the data namespace.  Example

Namespace1:

<ElementType name="row">
        <AttributeType name="column1" .../>
        <AttributeType name="column2" .../>
        <AttributeType name="column3" .../>
        ....
</ElementType>

Namespace2:

<row column1="value" column3="value"></row>

The reason I did not use a variable in my code below is because I am
processing attributes of each row in a for-each and I want to compare
against the attributes listed in the schema (because some attributes do not
exist in the namespace 2 data, like above, column2 is missing) so I am
checking to see if it is the correct value to output in that <td> cell.
Anyways I cannot use a variable (I thought) in the loop because you cannot
reassign the value of a variable.



April Fleming

Information Services

Dixon Ticonderoga Company

407-829-9000 ext. 153


-----Original Message-----
From: David Carlisle [mailto:davidc(_at_)nag(_dot_)co(_dot_)uk] 
Sent: Thursday, May 13, 2004 11:10 AM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Cc: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: Re: [xsl] two namespaces and a position problem


<xsl:variable name="x" select="position()"/>

s:AttributeType[position()]
means
s:AttributeType[position()=position()]
so the filter is always true so it is the same as
s:AttributeType

you want


<xsl:variable name="x" select="position()"/>
....
s:AttributeType[position()=$x]
although thi sis actually a strange thing to want as $x is the position
in your for-each which is
<xsl:for-each select="./@*">
and as the order of attributes is system-specific and unspecied your
current position number is essentially arbitrary.

David

-- 
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04


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