I just read the post thoroughly and realized he said he is getting out if he
only has one node. I'm sure that is the case.
Check out something like w3schools.com or topxml.com for some decent
tutorials and references.
-----Original Message-----
From: Josh Canfield [mailto:Josh(_dot_)Canfield(_at_)plumtree(_dot_)com]
Sent: Tuesday, May 04, 2004 7:00 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: RE: [xsl] XSL-output for xml without parent node
It can't be this easy, I'm sure you'd get an error if this was true, but you
are wrapping your RESULT elements in a node, right?
I tried your xsl with this xml:
<root>
<RESULT ID="1" NAME="te"/>
<RESULT ID="2" NAME="tes"/>
<RESULT ID="3" NAME="tess"/>
</root>
and got this result:
<html>
<body>123</body>
</html>
Josh
-----Original Message-----
From: Bret [mailto:laker_66(_at_)yahoo(_dot_)com]
Sent: Tuesday, May 04, 2004 2:04 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] XSL-output for xml without parent node
Hi!
I have the following xml .
<RESULT ID="1" NAME="te"/>
<RESULT ID="2" NAME="tes"/>
<RESULT ID="3" NAME="tess"/>
I have the following xsl
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xml:space="preserve">
<xsl:template match="/">
<html>
<body>
<xsl:for-each select="//RESULT">
<xsl:value-of select="@ID"/>
</xsl:for-each>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
when i use the following xsl i'm not getting any
output . I'm guessing it has to
do with <xsl:for-each select="//RESULT"> .
I do get output if i have only one record in the XML
file .
Any help appreciated .
Thanks!!!!
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