It can't be this easy, I'm sure you'd get an error if this was true, but you
are wrapping your RESULT elements in a node, right?
I tried your xsl with this xml:
<root>
<RESULT ID="1" NAME="te"/>
<RESULT ID="2" NAME="tes"/>
<RESULT ID="3" NAME="tess"/>
</root>
and got this result:
<html>
<body>123</body>
</html>
Josh
-----Original Message-----
From: Bret [mailto:laker_66(_at_)yahoo(_dot_)com]
Sent: Tuesday, May 04, 2004 2:04 PM
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] XSL-output for xml without parent node
Hi!
I have the following xml .
<RESULT ID="1" NAME="te"/>
<RESULT ID="2" NAME="tes"/>
<RESULT ID="3" NAME="tess"/>
I have the following xsl
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xml:space="preserve">
<xsl:template match="/">
<html>
<body>
<xsl:for-each select="//RESULT">
<xsl:value-of select="@ID"/>
</xsl:for-each>
</body>
</html>
</xsl:template>
</xsl:stylesheet>
when i use the following xsl i'm not getting any
output . I'm guessing it has to
do with <xsl:for-each select="//RESULT"> .
I do get output if i have only one record in the XML
file .
Any help appreciated .
Thanks!!!!
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