Michael:
My goal is to use the xsl to split a large xml into multple smaller xml
files and save them on the disk. I intend to use Ant task to execute it.
So, the file name and directory where the splitted file should be saved in
will be determined at run-time. That's why I tried to define variables for
both directory and file name in my xsl.
How can I achieve this goal? I read about saxon extension saxon:output and
xsl:result-document. Which one is good for me for my task? How can I
instruct the xsl processor what the directory the output file should be
saved at using href attributes? and without using -o .
Thank you.
Qin
----------------------------------------------------------------------------------------
This is a PRIVATE message. If you are not the intended recipient, please
delete without copying and kindly advise us by e-mail of the mistake in
delivery. NOTE: Regardless of content, this e-mail shall not operate to
bind CSC to any order or other contract unless pursuant to explicit written
agreement or government initiative expressly permitting the use of e-mail
for such purpose.
----------------------------------------------------------------------------------------
"Michael Kay"
<mhk To:
<xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com>
@mhk.me.uk> cc:
Subject: RE: Re: [xsl] how to
split one xml to multiple xml
05/03/04 11:06 files
AM
Please respond
to xsl-list
Rerun the xsl using saxon7.jar. I got this error:
D:\projects\epubs_xslt\src\gmemd\xml\cat\cat701>java -jar
..\..\..\..\..\lib\sax
on7.jar cat701.xml ..\..\..\xsl\createCatToc.xsl
Error at result-document on line 11 of
file:/D:/projects/epubs_xslt/src/gmemd/xm
l/cat/cat701/../../../xsl/createCatToc.xsl:
The system identifier of the principal output file is unknown
Transformation failed: Run-time errors were reported
What does it mean?
It means you haven't specified the -o option on the command line, or the
equivalent in the API. This is needed for resolving a relative URI in the
href attribute.
I tried to create another variable to specify the
directory like this:
<xsl:variable name="dir" select="d:\results" />
But I got the error stating "XPath syntax error in {D:/results}:
QName cannot end with colon: {D:}
Transformation failed: Failed to compile stylesheet. 1 error detected.
The value of the select attribute of xsl:variable is an XPath expression.
You probably meant to write
<xsl:variable name="dir" select="'d:\results'" />
but that wouldn't do you much good either, because the href value must be a
URI, not a filename.
Michael Kay
--+------------------------------------------------------------------
XSL-List info and archive: http://www.mulberrytech.com/xsl/xsl-list
To unsubscribe, go to: http://lists.mulberrytech.com/xsl-list/
or e-mail: <mailto:xsl-list-unsubscribe(_at_)lists(_dot_)mulberrytech(_dot_)com>
--+--