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Re: Sorting unique and sub-total problem

2004-06-03 09:10:18
Hi Roger,
  Please try the XSL -

<?xml version="1.0" encoding="UTF-8"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
xmlns:xalan="http://xml.apache.org/xalan";>
<xsl:output method="text" version="1.0"
encoding="UTF-8" indent="yes"/>
        
<xsl:key name="by-card-number" match="ITEM"
use="CARD/@number"/>
        
<xsl:template match="/root">
  <xsl:variable name="rtf1">
    <xsl:for-each select="ITEM">
      <xsl:if test="generate-id(.) =
generate-id(key('by-card-number', CARD/@number)[1])">
        <group>
          <number>
            <xsl:value-of select="CARD/@number"/>
          </number>
          <xsl:for-each select="key('by-card-number',
CARD/@number)">
            <amount>
              <xsl:value-of select="AMOUNT/@amt"/>
            </amount>
          </xsl:for-each>
        </group>
      </xsl:if>
    </xsl:for-each>
  </xsl:variable>
                
  <xsl:variable name="rtf2">
    <xsl:for-each select="xalan:nodeset($rtf1)/group">
      <xsl:sort select="number" order="ascending"
data-type="number" />
        <xsl:copy-of select="." />
    </xsl:for-each>
  </xsl:variable>
                
  <xsl:for-each select="xalan:nodeset($rtf2)/group">
     Card: <xsl:value-of select="number" />  Total:
<xsl:value-of select="sum(amount)" />
  </xsl:for-each>

</xsl:template>
</xsl:stylesheet>

Regards,
Mukul

--- roger(_dot_)wyatt(_at_)nomadsoft(_dot_)com wrote:

I am struggling with what is turning out to be a
rather nasty problem using
FOP  0.20.5 .  I have a set of unordered nodes along
the lines of :...

      <ITEM item_id='1'>  <CARD number='123456789'
\>  <AMOUNT amt='100'\>
</ITEM>
      <ITEM item_id='2'>  <CARD number='987654321'
\>  <AMOUNT amt='30'\>
</ITEM>
      <ITEM item_id='3'>  <CARD number='123456789'
\>  <AMOUNT amt='200'\>
</ITEM>
      <ITEM item_id='4'>  <CARD number='123456789'
\>  <AMOUNT amt='50'\>
</ITEM>


The <ITEM> nodes can be in any order.  What I would
like to get at the end
is the following out put.

      Card: 123456789  Total:350
      Card: 987654321  Total:  30

At the moment I can't even sort unique! I have tried
to sort the nodes and
then compare the current node to the following
sibling, using...

<xsl:for-each select=".//ITEM" >
<xsl:sort select="CARD/@number" order="ascending" />
      <xsl:if test="./CARD/@number[ not
(.=following-sibling::ITEM/CARD/@number) ]">
            ....print number etc. etc....

But what I have found is that the following sibling
is as it would be if
the nodes have not been ordered.  I have proven this
to myself using
something along the lines of...

<xsl:for-each select=".//ITEM" >
<xsl:sort select="CARD/@number" order="ascending" />
      <fo:block>
            CUR NUMBER: <xsl:value-of
select=".//CARD/@number"/>
            NXT NUMBER: <xsl:value-of
select="following-sibling::
*/CARD/@number"/>
            CUR ID IS: <xsl:value-of
select="./@item_id"/>
            NXT ID IS: <xsl:value-of
select="following-sibling::
*/@item_id"/>
      </fo:block>
</xsl:for-each>

I fear that the only way to deal with this is to use
XSLT to preorder the
nodes and then use a 2nd script using the same
approach as described.
Alternatively I could go right back to the process
that originally created
the XML file and order / sub total from there...
something I really want to
avoid if at all possible.

Is there another approach I can take ?  Am I
expecting too much from XSLT
with all this... ?

Thanks for any help in advance...

Roger.


***************************************
Roger Wyatt
Principal Consultant
Nomad Software Ltd.
***************************************
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