Your variable $employeeList is a result tree fragment and XSLT 1.0 does not
allow you to use an RTF in a path expression. You need the xx:node-set()
extension function, or an XSLT 2.0 processor, or an XSLT 1.0 processor that
relaxes this rule.
Michael Kay
http://www.saxonica.com/
P.S. You might not be able to make sense of the error message, but there are
many people on this list who can, and who would be able to answer your
question more quickly if you quoted it.
-----Original Message-----
From: Ranjan K. Baisak [mailto:ranjanbaisak(_at_)yahoo(_dot_)com]
Sent: 02 September 2004 14:35
To: xsl-list(_at_)lists(_dot_)mulberrytech(_dot_)com
Subject: [xsl] for-each loop in node set variable gives error
Hello List,
My stylesheet contains following
declarations
declaration 1:
<xsl:variable name="employeeList">
<xsl:for-each select="//employee/*[name()!='max']">
<xsl:if test="count(key('employee', @id))=0">
<xsl:copy>
<xsl:copy-of
select="property[(_at_)name='cast']/@val"/>
<xsl:copy-of select="@name"/>
<xsl:copy-of
select="property[(_at_)name='language']"/>
</xsl:copy>
</xsl:if>
</xsl:for-each>
</xsl:variable>
declaration 2:
<xsl:variable name="generatedEmployees">
<xsl:for-each select="$employeeList/*">
<xsl:sort select="@val"/>
<xsl:copy-of select="."/>
</xsl:for-each>
</xsl:variable>
for-each loop for $employeeList/* in declaration 2
gives error. I don't understand why it gives error.
Any clue?
regards,
Ranjan
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